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Home/ Questions/Q 5942215
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T16:13:14+00:00 2026-05-22T16:13:14+00:00

Is the following singleton implementation data-race free? static std::atomic<Tp *> m_instance; … static Tp

  • 0

Is the following singleton implementation data-race free?

static std::atomic<Tp *> m_instance;
...

static Tp &
instance()
{
    if (!m_instance.load(std::memory_order_relaxed))
    {
        std::lock_guard<std::mutex> lock(m_mutex);
        if (!m_instance.load(std::memory_order_acquire))
        {
            Tp * i = new Tp;
            m_instance.store(i, std::memory_order_release);    
        }    
    }

    return * m_instance.load(std::memory_order_relaxed);
}

Is the std::memory_model_acquire of the load operation superfluous? Is it possible to further relax both load and store operations by switching them to std::memory_order_relaxed? In that case, is the acquire/release semantic of std::mutex enough to guarantee its correctness, or a further std::atomic_thread_fence(std::memory_order_release) is also required to ensure that the writes to memory of the constructor happen before the relaxed store? Yet, is the use of fence equivalent to have the store with memory_order_release?

EDIT: Thanks to the answer of John, I came up with the following implementation that should be data-race free. Even though the inner load could be non-atomic at all, I decided to leave a relaxed load in that it does not affect the performance. In comparison to always have an outer load with the acquire memory order, the thread_local machinery improves the performance of accessing the instance of about an order of magnitude.

static Tp &
instance()
{
    static thread_local Tp *instance;

    if (!instance && 
        !(instance = m_instance.load(std::memory_order_acquire)))
    {
        std::lock_guard<std::mutex> lock(m_mutex);
        if (!(instance = m_instance.load(std::memory_order_relaxed)))
        {
            instance = new Tp; 
            m_instance.store(instance, std::memory_order_release);    
        }    
    }
    return *instance;
}
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  1. Editorial Team
    Editorial Team
    2026-05-22T16:13:15+00:00Added an answer on May 22, 2026 at 4:13 pm

    That implementation is not race-free. The atomic store of the singleton, while it uses release semantics, will only synchronize with the matching acquire operation—that is, the load operation that is already guarded by the mutex.

    It’s possible that the outer relaxed load would read a non-null pointer before the locking thread finished initializing the singleton.

    The acquire that is guarded by the lock, on the other hand, is redundant. It will synchronize with any store with release semantics on another thread, but at that point (thanks to the mutex) the only thread that can possibly store is the current thread. That load doesn’t even need to be atomic—no stores can happen from another thread.

    See Anthony Williams’ series on C++0x multithreading.

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