Question

Is the new operator guaranteed to allocate a continuous chunk of heap memory? I.e. is

objects=new Base[1024];

in terms of memory allocation the same as

objects=(Base*)malloc(1024*sizeof(base));

or can there be gaps?

Answer 1

Yes, the memory will be continuous. In terms of allocation, it’s the same as the malloc version, but there are several differences (calls to constructor, new doesn’t return NULL, malloc doesn’t throw exceptions, etc.`).

Note that you can’t mix up new[] with delete or free, you have to use delete[] objects to free the memory.