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Home/ Questions/Q 9227255
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T05:01:37+00:00 2026-06-18T05:01:37+00:00

Is there a better way to do the following: if column_sort == ‘size’: if

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Is there a better way to do the following:

    if column_sort == 'size':
        if sort == 'desc':
            results = results.order_by('-size')
        else:
            results = results.order_by('size')
    elif column_sort == 'modified':
        if sort == 'desc':
            results = results.order_by('-last_modified')
        else:
            results = results.order_by('last_modified')
    else:
        if sort == 'desc':
            results = results.order_by('-path')
        else:
            results = results.order_by('path')
    results = results[:100]

For example, a way in which to reverse the query order?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T05:01:38+00:00Added an answer on June 18, 2026 at 5:01 am

    How about you just write the code once?

    valid_column_sorts = ['size', 'last_modified', 'path']
    
    if column_sort in valid_column_sorts:
        if sort == 'desc':
            column_sort = '-' + column_sort
        results = results.order_by(column_sort)
    

    Oh yeah, I see that there’s some difference between sort fields and values, in which case you need a simple map, like results.order_by(col_map[column_sort])

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