Question

Is there a better way to implement a paging solution using dict than this?

I have a dict with image names and URLs.
I need to 16 key value pairs at a time depending on the user’s request, i.e. page number.
It’s a kind of paging solution.
I can implement this like:

For example :

dict = {'g1':'first', 'g2':'second', ... }

Now I can create a mapping of the keys to numbers using:

ordered={}

for i, j in enumerate(dict):
    ordered[i]=j

And then retrieve them:

dicttosent={}

for i in range(paegnumber, pagenumber+16):
  dicttosent[ordered[i]] = dict[ordered[i]]

Is this a proper method, or will this give random results?

Answer 1

• Store g1, g2, etc in a list called imagelist
• Fetch the pages using imagelist[pagenumber: pagenumber+16].
• Use your original dict (image numbers to urls) to lookup the url for each of those 16 imagenames.