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Home/ Questions/Q 6065725
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T09:25:24+00:00 2026-05-23T09:25:24+00:00

Is there a difference between this: average = (x1+x2)/2; deviation1 = x1 -average; deviation2

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Is there a difference between this:

average = (x1+x2)/2;
deviation1 = x1 -average;
deviation2 = x2 -average;
variance = deviation1*deviation1 + deviation2*deviation2;

and this:

average2 = (x1+x2);
deviation1 = 2*x1 -average2;
deviation2 = 2*x2 -average2;
variance = (deviation1*deviation1 + deviation2*deviation2) / 4;

Note that in the second version I am trying to delay division as late as possible. Does the second version [delay divisions] increase accuracy in general?

Snippet above is only intended as an example, I am not trying to optimize this particular snippet.

BTW, I am asking about division in general, not just by 2 or a power of 2 as they reduce to simple shifts in IEEE 754 representation. I took division by 2, just to illustrate the issue using a very simple example.

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  1. Editorial Team
    Editorial Team
    2026-05-23T09:25:24+00:00Added an answer on May 23, 2026 at 9:25 am

    There’s nothing to be gained from this. You are only changing the scale but you’d don’t get any more significant figures in your calculation.

    The Wikipedia article on variance explains at a high level some of the options for calculation variance in a robust fashion.

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