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Editorial Team
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Asked: 2026-05-23T10:19:10+00:00

Is there a difference if it is the first use of the variable or

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Is there a difference if it is the first use of the variable or not. For example are a and b treated differently?

void f(bool&a, bool& b)
{
    ...
    a=false;
    boost::this_thread::sleep...//1 sec sleep
    a=true;
    b=true;
    ...
}

EDIT: people asked why I want to know this.
1. I would like to have some way to tell the compiler not to optimize(swap the order of the execution of the instructions) in some function, and using atomic and or mutexes is much more complicated than using sleep(and in my case sleeping is not a performance problem).
2. Like I said this is generally important to know.

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1 Answer

  1. Editorial Team

    We can’t really tell. On scenario could be that the compiler has full introspection to your function at the calling site (and possibly does inline it), in which case it can jumble your function with the caller, and then do optimizations appropriately.

    It could then e.g. completely optimize away a and b because there is no code that depends on a and b. Or it might see that you violate aliasing rules so that a and b refer to the same entity, and then merge them according to your program flow.

    But it could also be that you tell the compiler to not optimize at all, e.g. with g++’s -O0 flag, in which case not much will happen.

    The only proof for your particular platform *, can be made by looking at the generated assembly, or by telling the compiler to please output some log about what it optimizes (g++ has many flags for that).

    * compiler+flags used to compile compiler+version+add-ons, hardware, operating system; even the weather might be relevant if your compiler omits some optimizations if it takes to long [which would actually be cool feature for debug builds, imho]

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