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Home/ Questions/Q 9235983
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T07:10:52+00:00 2026-06-18T07:10:52+00:00

Is there a function like std::for_each that directly passes the iterators instead of the

  • 0

Is there a function like std::for_each that directly passes the iterators instead of the result of dereferencing them?

What we have

std::vector<int> ints;
std::for_each(ints.begin(), ints.end(),
[](int i)
{
  //how to get the iterator of this element???
}

what I am searching for

for_each_iterator(ints.begin(), ints.end(),
[](const std::vector<int>::const_iterator &i)
{
  //we know the iterator here
}

Of course it is fairly trivial to write such a function, but I am asking if there exists a standard solution from std::, std::tr1:: or boost::

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T07:10:53+00:00Added an answer on June 18, 2026 at 7:10 am

    There is no such thing in the Standard library. But it is not that hard to implement it yourself:

    template<typename It, typename Functor >
    void iterate(It begin, It end, Functor && f)
    {
        while ( begin != end ) { f(begin); ++begin; }
    }
    

    And use it as:

    iterate(ints.begin(), ints.end(), [](std::vector<int>::iterator it)
                  {
                     //use it
                  });
    

    Or use manual loop.

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