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Home/ Questions/Q 8392877
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T19:38:09+00:00 2026-06-09T19:38:09+00:00

Is there a more concise way to split a list into two lists by

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Is there a more concise way to split a list into two lists by a predicate?

errors, okays = [], []
for r in results:
    if success_condition(r):
        okays.append(r)
    else:
        errors.append(r)

I understand that this can be turned into an ugly one-liner using reduce; this is not what I’m looking for.

Update: calculating success_condition only once per element is desirable.

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  1. Editorial Team
    Editorial Team
    2026-06-09T19:38:10+00:00Added an answer on June 9, 2026 at 7:38 pm

    Maybe

    for r in results:
        (okays if success_condition(r) else errors).append(r)
    

    But that doesn’t look/feel very Pythonic.


    Not directly relevant, but if one is looking for efficiency, caching the method look-ups would be better:

    okays_append = okays.append
    errors_append = errors.append
    
    for r in results:
        (okays_append if success_condition(r) else errors_append)(r)
    

    Which is even less Pythonic.

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