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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T03:44:21+00:00 2026-06-16T03:44:21+00:00

Is there a more efficient way to generate a 10 kBit (10,000 bits) random

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Is there a more efficient way to generate a 10 kBit (10,000 bits) random binary sequence in Python than appending 0s and 1s in a loop?

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  1. Editorial Team
    Editorial Team
    2026-06-16T03:44:22+00:00Added an answer on June 16, 2026 at 3:44 am

    If you want a random binary sequence then it’s probably quickest just to generate a random integer in the appropriate range:

    import random
    s = random.randint(0, 2**10000 - 1)
    

    After this it really depends on what you want to do with your binary sequence. You can query individual bits using bitwise operations:

    s & (1 << x)  # is bit x set?
    

    or you could use a library like bitarray or bitstring if you want to make checking, setting slicing etc. easier:

    from bitstring import BitArray
    b = BitArray(uint=s, length=10000)
    p, = b.find('0b000000')
    if b[99]:
        b[100] = False
    ...
    
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