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Asked: May 11, 20262026-05-11T02:03:44+00:00 2026-05-11T02:03:44+00:00

Is there a POSIX function that will give me the size of a directory

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Is there a POSIX function that will give me the size of a directory (including all sub-folders), roughly equivalent to ‘du -s somepath‘?

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  1. 2026-05-11T02:03:45+00:00Added an answer on May 11, 2026 at 2:03 am
    $ man nftw 

    NAME

    ftw, nftw – file tree walk

    DESCRIPTION

    ftw() walks through the directory tree that is located under the directory dirpath, and calls fn() once for each entry in the tree. By default, directories are handled before the files and subdirectories they contain (pre-order traversal).

    CONFORMING TO

    POSIX.1-2001, SVr4, SUSv1.

    Simple example

    #include <stdio.h> #include <errno.h> #include <unistd.h> #include <sys/types.h> #include <sys/stat.h>  static unsigned int total = 0;  int sum(const char *fpath, const struct stat *sb, int typeflag) {     total += sb->st_size;     return 0; }  int main(int argc, char **argv) {     if (!argv[1] || access(argv[1], R_OK)) {         return 1;     }     if (ftw(argv[1], &sum, 1)) {         perror('ftw');         return 2;     }     printf('%s: %u\n', argv[1], total);     return 0; } 
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