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Home/ Questions/Q 8845737
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T11:48:20+00:00 2026-06-14T11:48:20+00:00

Is there a reason why int[] myArray = new int[0]; compiles? Is there any

  • 0

Is there a reason why

int[] myArray = new int[0];

compiles?

Is there any use of such an expression?

myArray[0] = 1;

gives java.lang.ArrayIndexOutOfBoundsException.

if (myArray == null) {
    System.out.println("myArray is null.");
} else {
    System.out.println("myArray is not null.");
}

gives myArray is not null..

So I can’t see a reason why int[] myArray = new int[0] should be preferred over myArray = null;.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T11:48:21+00:00Added an answer on June 14, 2026 at 11:48 am

    It’s just for reducing null checks.

    You can iterate on empty array but can not iterate on null.

    Consider the code:

    for (Integer i: myArray) {
       System.out.println(i);
    }
    

    On empty array it prints nothing, on null it causes NullPointerException.

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