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Home/ Questions/Q 876365
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T11:25:13+00:00 2026-05-15T11:25:13+00:00

Is there a simple way to forward to a member function with a matching

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Is there a simple way to forward to a member function with a matching function signature?

typedef std::tr1::function<int(int,int,int,int)> TheFn;
class C
{
    int MemberFn(int,int,int,int) { return 0; }

    TheFn getFn() { 
        //is there a simpler way to write the following line?
        return [this](int a,int b,int c,int d){ return this->MemberFn(a,b,c,d); };
    } 
};
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T11:25:14+00:00Added an answer on May 15, 2026 at 11:25 am

    Have you tried bind?

    // C++0x update
    struct test {
       void f( int, int, int, int );
    };
    int main()
    {
       std::function<void (int,int,int,int)> fn;
       test t;
       fn = std::bind( &t::f, &t, 
               std::placeholders::_1, 
               std::placeholders::_2, 
               std::placeholders::_3, 
               std::placeholders::_4 );
       fn( 1, 2, 3, 4 ); // t.f( 1, 2, 3, 4 )
    }
    

    I have left the full qualification of all elements, but std::placeholders applied so many times don’t really help readability… I guess a using std::placeholders would not hurt at all:

    using std::placeholders;
    fn = std::bind( &t::f, &t, _1, _2, _3, _4 );
    

    EDIT: To make it closer to the question code, so that it is clearer that this has the exact same functionality that the original code:

    typedef std::function<int(int,int,int,int)> TheFn;
    class C {
       int MemberFn( int, int, int, int ) { return 0; }
    public:
       int MemberFn2(int,int,int,int) { return 2; }
       TheFn getFn() {
          using std::placeholders;
          return std::bind( &C::MemberFn, this, _1, _2, _3, _4 );
       }
    };
    int main() {
       C instance;
       TheFn fn1 = instance.getFn();
       std::cout << fn1( 1, 2, 3, 4 ) << std::endl; // 0
    
       using std::placeholders;
       TheFn fn2 = std::bind( &C::MemberFn2, &instance, _1, _2, _3, _4 );
       std::cout << fn2( 1, 2, 3, 4 ) << std::endl;
    }
    

    As you can see in both cases you are doing the same. I have used private and public methods for the example to show that when you bind, the member method access level is checked at the place of bind, not at the place of call. So even if MemberFn is private within the class you can call it through the binded functor. If the member is public, you can actually bind from outside of the class.

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