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Home/ Questions/Q 3979332
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T05:09:25+00:00 2026-05-20T05:09:25+00:00

Is there a standard method to repr the call that resulted in a given

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Is there a standard method to repr the call that resulted in a given stack frame in Python? Failing that, is there a nice way to do it manually?

As an example:

def some_call(*args, **kwargs):
    print('{}({})'.format(
         'some_call',
         ', '.join(itertools.chain(
             map(repr, args),
             ('{}={!r}'.format(k, kwargs[k]) for k in kwargs)))))

>>> some_call(1, 2, a=3)
some_call(1, 2, a=3)

I’m attempting to log certain calls, and am writing a decorator that logs calls to the wrapped function with full details. Am I going about this wrong?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T05:09:26+00:00Added an answer on May 20, 2026 at 5:09 am

    I’m not quite sure what you’re asking, but you can use the inspect module to get all the current stack info.

    f = inspect.currentframe()
    print(f.f_locals)
    print(inspect.getframeinfo(f))
    

    You can regenerate the calling of your current frame using inspect.getargvalues, and format it to your liking

    def some_call(arg1, arg2, *args, **kwargs):
        f = inspect.currentframe()
        fn_name = inspect.getframeinfo(f)[2]
        arginfo = inspect.getargvalues(f)
        args = [repr(arginfo.locals[arg]) for arg in arginfo.args]
        varargs = [repr(x) for x in arginfo.locals[arginfo.varargs]]
        kwargs = [', '.join(str(k)+"="+repr(v) for k,v in 
            arginfo.locals[arginfo.keywords].items())]
        print('{0}({1})'.format(fn_name, ', '.join(args + varargs + kwargs)))
    
    >>> some_call(1, 2, "hi", kw1="frob")
    some_call(1, 2, 'hi', kw1='frob')
    
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