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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T08:19:59+00:00 2026-06-18T08:19:59+00:00

Is there a straightforward way to generate all possible permutations of a vector of

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Is there a straightforward way to generate all possible permutations of a vector of integers (1 to max 999) that specifically excludes duplicated elements?

For example, for a vector with three elements in a range of 1 to 9 the sequence 1 2 3 would be acceptable, as would 1 2 9 but 1 2 2 would be invalid. The sequence must contain exactly n elements (in this case, three). EDIT: to avoid confusion, the order is significant, so 1 2 9 and 9 2 1 are both valid and required.

There are many questions on permutations and combinations using R on SO (such as this and this) but none that seem to fit this particular case. I’m hoping there’s an obscure base R or package function out there that will take care of it without me having to write a graceless function myself.

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  1. Editorial Team
    Editorial Team
    2026-06-18T08:20:00+00:00Added an answer on June 18, 2026 at 8:20 am

    Using gtools package:

    require(gtools)
    permutations(n = 9, r = 3, v = 1:9)
    # n -> size of source vector
    # r -> size of target vector
    # v -> source vector, defaults to 1:n
    # repeats.allowed = FALSE (default)
    
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