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Home/ Questions/Q 7615857
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T02:44:47+00:00 2026-05-31T02:44:47+00:00

Is there a way I can make my custom class be passed by reference

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Is there a way I can make my custom class be passed by reference only?

Basically, I have the following class:

class A{
private:
  int _x;
public:
  A(int y){
    _x = y;
  }
};

Can I make it to where I can ONLY pass it by reference? And it will throw a compile time error otherwise?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T02:44:48+00:00Added an answer on May 31, 2026 at 2:44 am

    Several people have suggested making the copy constructor private. This is a mostly good solution to the problem however it’s not complete. It still allows the type itself to accidentally pass itself by value. A more thorough solution is to declare the copy constructor private and then never implement it.

    class A{
    private:
      // Prevent value copying
      A(const A&);
    
      int _x;
    public:
      A(int y){
        _x = y;
      }
    };
    

    Note: As @DeadMG points out, in C++11 using delete is preferred.

    A(const A&) = delete;
    
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