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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T07:12:17+00:00 2026-05-14T07:12:17+00:00

Is there a way to avoid adding a second LEFT JOIN for the table

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Is there a way to avoid adding a second LEFT JOIN for the table “social_mcouple” to query where social_members.m_id = social_mcouple.c_id below?

$res = @mysql_query("SELECT *, DATE_FORMAT(m_lld,'%m/%d/%y') AS m_lld_formatted FROM social_members 
        LEFT JOIN social_member_types ON t_id=m_type WHERE m_user='".$en['user']."'");
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  1. Editorial Team
    Editorial Team
    2026-05-14T07:12:18+00:00Added an answer on May 14, 2026 at 7:12 am

    If there will always be a social_mcouple that corresponds to social_members, or you’re only interested in rows where there is a correspondence then you may use an INNER JOIN. If you need all social_members regardless of whether there is a corresponding social_mcouple then you will need a LEFT JOIN. The LEFT JOIN will give you all rows with social_mcouple.* set to NULL where there is not a match.

    The performance hit will really depend on the size of your datasets.

    EDIT: adding a sample UNION query.

    $res = @mysql_query("
    (SELECT social_members.*, social_member_types.*, DATE_FORMAT(m_lld,'%m/%d/%y') AS m_lld_formatted,
      NULL AS mcouple1, NULL AS mcouple2, NULL AS mcouple3
    FROM social_members 
    LEFT JOIN social_member_types ON t_id=m_type
    WHERE m_user='".$en['user']."' AND m_type != 2)
    
    UNION
    
    (SELECT social_members.*, social_member_types.*, DATE_FORMAT(m_lld,'%m/%d/%y') AS m_lld_formatted,
        social_mcouple.mcouple1, social_mcouple.mcouple2, social_mcouple.mcouple3
    FROM social_members 
    LEFT JOIN social_member_types ON t_id=m_type
         JOIN social_mcouple ON social_members.m_id = social_mcouple.c_id
    WHERE m_user='".$en['user']."' AND m_type = 2)
    ");
    
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