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Home/ Questions/Q 6185761
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T01:46:16+00:00 2026-05-24T01:46:16+00:00

Is there a way to by using some metaprogramming trick make situation like this

  • 0

Is there a way to by using some metaprogramming trick make situation like this works:

int* get();//this fnc returns pointer to int OR nullptr
int k = 1;
//this is the operator which is supposed to compare value and pointer
template<class T>
bool operator!=(const T& left, const T* right)
{
    if (right)
    {
        return left != *right;
    }
    else
    {
        return false;
    }
}


//And this is the code fragment which interests me most  
if (k != get())
{
    ///

}

The crux is that I would like NOT TO change this line k != get() and yet for some reason my operator!= seems not to work. What’s the problem?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T01:46:17+00:00Added an answer on May 24, 2026 at 1:46 am

    As already mentioned in other answers that you cannot have operator != for non userdefined types like int, char and so on.

    One option is to wrap int inside your user defined struct and achieve the goal.

    struct Int
    {
      int i;
      // define all the necessary operators/constructor who deal with 'int'
      Int(int x) : i(x) {}
      bool operator != (const int* right)
      {
        return (right)? (i != *right) : false;
      }
    };
    

    Now declare

    Int k = 1;
    
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