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Home/ Questions/Q 7614477
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T02:24:48+00:00 2026-05-31T02:24:48+00:00

Is there a way to check if two elements have the same class name?

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Is there a way to check if two elements have the same class name? My code looks like this…

<body class="foo bar cats">
<a href="#" class="foo">Link</a>
<a href="#" class="puppies">Link</a>

What I want to do is add another class to the foo link if it matches a class in the body. How would I check if one of the classes in my links matches a class in the body with jQuery?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T02:24:49+00:00Added an answer on May 31, 2026 at 2:24 am

    I’d suggest:

    $('a').each(
        function() {
            var classes = this.classList;
            for (var i=0,len=classes.length; i<len; i++){
                if ($('body').hasClass(classes[i])){
                    $(this).addClass('bodySharesClass');
                }
            }
        });​
    

    JS Fiddle demo.


    Edited to try and account for Internet Explorer’s inability to understand/use/implement .classList:

    if (!document.createElement().classList){
        var useAttr = true;
    }
    
    $('a').each(
        function(i) {
            var classes = [];
            if (!useAttr){            
                classes = this.classList;
            }
            else {
                classes = $(this).attr('class');
            }
            for (var i=0,len=classes.length; i<len; i++){
                if ($('body').hasClass(classes[i])){
                    $(this).addClass('bodySharesClass');
                }
            }
        });
    

    JS Fiddle demo.


    Edited because it appears my previous attempt, to account for IE, failed. Sigh. Still! This approach should work, albeit I can’t test it, as I’m without both IE and Windows:

    $('a').each(
        function(i) {
            var classes = this.className.split(/\s+/);
            for (var i=0,len=classes.length; i<len; i++){
                if ($('body').hasClass(classes[i])){
                    $(this).addClass('bodySharesClass');
                }
            }
        });
    

    JS Fiddle demo.

    References:

    • classList.
    • hasClass().
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