Question

Is there a way to convert an array to an integer, i have the follow method but it does not seem to work:

int8_t x_array[18] = {0,1,1,0,1,0,1,0,1,0,1,0,0,0,0,0,1,1};
int32_t numb;

for (int8_t j=0;j<19;j++)
{
   numb = numb + pow(2, i)*x_array[i];
}

Is there a reason for this??

PS: this is a follow up question from a previous question I had posted
Joining outputs from switches
I have edited the question to say why the method suggested is not working.

In essence what I am trying to do is create a program, in RAPIDILITTE which is a simulator software, to sample a PS input (proximity sensor system) every millisecond which is 18-bit digital input. The input is represented by toggle switches 0-17(18-bits) which is located on port 2. the input need to be normalised between 0-9999)

The main problem is that( which I have mentioned in the previous posted question) I can only access one pin at a time and not the read the whole port at once. I have tried many ways to read the pins and combine them into one variable convert it to a natural number and then normalise the input. In the end I believe the best way to do this is to put the each pins reading into a array[18] and then covert this into a variable and then normalise it.

Answer 1

numb is never initialized. You’re also iterating past the last element in the array (j < 19 should be j< 18). Additionally, you never declared i… it appears you meant j.

I believe you’re trying to convert the array of bits into a single int32_t. Presumably the array is in ascending order of significance i.e. from least- to most-significant bit.

int8_t x_array[18] = { 0, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 0, 0, 0, 1, 1 };
int32_t numb = 0;
for (int8_t j = 0; j < 18; ++j) {
  numb |= x_array[j] << j;
}

You don’t need to use pow here, since pow(2, j) is equivalent to 1 << j.