Question

is there a way to create an alias for a scala keyword? in particular i have some boilerplate syntax that involves “val” and in order to make it easier to read i’d like to be able to type something “@@” instead and have that translated to val.

Edit:

In some cases, it might be very convenient to be able to replace “lazy val”, not just “val”. The use case has to do with a function that acts as a python decorator. It looks like this:

lazy val function = Decorate(function_ _)
def function_(x: Int, ...) = { ... }

it would be a lot nicer if it looked like this:

@ function = Decorate(function_ _)
def function_(x: Int, ...) = { ... }

just so that there’s not a val stacked on top of a def, where both names are extremely similar. (the function_ name is not meant to be called, so it’s the cleanest to make the names similar.)

Answer 1

No, there isn’t.

(filler so SO will let me post)