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Home/ Questions/Q 7018813
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T23:06:03+00:00 2026-05-27T23:06:03+00:00

Is there a way to declare an argument as optional in the Go programming

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Is there a way to declare an argument as “optional” in the Go programming language?

Example of what I mean:

func doSomething(foo string, bar int) bool {
    //...
}

I want the parameter bar to be optional and default to 0 if nothing is passed through.

doSomething("foo")

would be the same as

doSomething("foo",0)

I’m unable to find anything about this matter in the official documentation about functions.

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  1. Editorial Team
    Editorial Team
    2026-05-27T23:06:04+00:00Added an answer on May 27, 2026 at 11:06 pm

    I don’t believe Go does support optional arguments to functions, though you can fake it with variadic functions. The C approach, if you don’t want to do that, is to pretend the language supports currying:

    func doSomethingNormally(foo string) bool {
        doSomething(foo, 0)
    }
    
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