Question

Is there a way to find out what the return type of a function (or even better of a function pointer) is ?

I’ve got the following code, which breaks when I use a void function pointer, but works fine for any other return type. The error I get when using a void function pointer from gcc 4.5 is:

error: void value not ignored as it ought to be

Which makes sense. So obviously I need to check if function pointer returns something, and then obtain the result and return it.

template <class F,typename R> class Instruction
{
  protected:
    F (func);
    R result;

  public:

   template <typename T>
   Instruction(T const& f)
   {
     func = &f;
   };

   template <typename A> void execute(A const& a)
   {
     result = (func)(a);
   };
   template <typename A> void execute(A const& a,A const& b)
   {
     result = (func)(a,b);
   };
   template <typename A> void execute(A const& a,A const& b,A const& c)
   {
     result = (func)(a,b,c);
   };
   R get_result()
   {
     return result;
   }; 
};

Normally I use a function pointer to a function which does something mostly arithmetic and I can take care of any return type at instantiation other than void functions. I’ve tried instantiating as:

     Instruction<ptr2func2,void> foo(bar);
     Instruction<ptr2func2,(*void)> foo(bar);

but in both cases it fails.

The second template argument at instantiation is used in order to define what the return type will be.

Answer 1

Try a template partial specialization on void:

template <class F> class Instruction<F, void>
{
  protected:
    F (func);

  public:

   template <typename T>
   Instruction(T const& f)
   {
     func = &f;
   };

   template <typename A> void execute(A const& a)
   {
     (func)(a);
   };
   template <typename A> void execute(A const& a,A const& b)
   {
     (func)(a,b);
   };
   template <typename A> void execute(A const& a,A const& b,A const& c)
   {
     (func)(a,b,c);
   };
};