Question

is there a way to get one level above or below directory from the one that is given?
For example ‘/a/b/c/’ directory was entered in a function.

So function would return:

lvl_down = '/a/b/'
lvl_up = '/a/b/c/d/'

I think you can do it using ‘re’ module (at least with one level below directory), but maybe there is more simple and better way to do it without regex?

Answer 1

I have no idea, how the function should know, that you want to go in directory d:

#!/usr/bin/python
import os.path

def lvl_down(path):
    return os.path.split(path)[0]

def lvl_up(path, up_dir):
    return os.path.join(path, up_dir)

print(lvl_down('a/b/c'))   # prints a/b
print(lvl_up('a/b/c','d')) # prints a/b/c/d

Note: Had another solution before, but os.path is a much better one.