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Home/ Questions/Q 647571
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T21:44:13+00:00 2026-05-13T21:44:13+00:00

Is there a way to have breakpoints hit when the action is caused by

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Is there a way to have breakpoints hit when the action is caused by the Visual Studio debugger?
For example, let’s say I have the following (I know you shouldn’t do this, just using it for argument’s sake):

public class Test
{
    int _X = -1;
    public int X { 
        get { return ++_X; } //Breakpoint here
        set { _X = value; } 
    }
}

And:

static void Main(string[] args)
{

        Test t = new Test();
        t.X = 1;  //Breakpoint here
        return;
}

If you pause at the breakpoint in Main, every time you “hover” the mouse pointer over “t.X”
(assuming you have the following Debugging option enabled – “Enable property evaluation and other implicit function calls”) or you evaluate the property in the “watch” window – it will increment the property but the breakpoint in the property’s “get” accessor will not be hit. Re-asking the question in a more specific context – is there a way to hit the breakpoint in the property’s “get” accessor when the evaluation is done by the debugger?

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  1. Editorial Team
    Editorial Team
    2026-05-13T21:44:13+00:00Added an answer on May 13, 2026 at 9:44 pm

    After some research on this topic, I learned about FuncEval, and after reading lots of things about FuncEval I was led to the following article:
    Stop Mid Func Eval, Nested Break States by Mr. SteveJS.
    In the article he explained that starting in VS2005 you could hit a breakpoint caused by a FuncEval if the evaluation was done from the "Immediate Window" instead of the Watch or "Quick Watch" windows. So, in the above example, entering

    ?t.X
    

    in the Immediate Window caused the breakpoint on the get accessor to be hit.

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