Question

Is there a way to hide/show a method if a certain constructor is used? i.e.:

public class SomeClass
{
    public SomeClass(string methodA)
    {

    }

    public SomeClass(int methodB)
    {

    }

    public string MethodA()
    {
        return "";
    }

    public int MethodB()
    {
        return 0;
    }
}

if SomeClass(string methodA) is used, then only MethodA() is available when I instance a new SomeClass object? The same when SomeClass(int methodB) is used, then MethodB() would be available?

Thank you all!

Answer 1

No, it’s not possible.

What’s more likely is that you want to use generics:

public interface IFoo<T>
{
    T Method();
}

public class IntFoo : IFoo<int>
{
    int value;
    public IntFoo(int value)
    {
        this.value = value;
    }

    public int Method()
    {
        return value;
    }
}

public class StringFoo : IFoo<string>
{
    string value;
    public StringFoo(string value)
    {
        this.value = value;
    }

    public string Method()
    {
        return value;
    }
}

If you don’t need to restrict it to just strings or ints (or don’t want to) then something like this might work, or even be better:

public class Foo<T>
{
    private T value;
    public Foo(T value)
    {
        this.value = value;
    }

    public T Method()
    {
        return value;
    }
}