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Home/ Questions/Q 9144081
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T10:10:55+00:00 2026-06-17T10:10:55+00:00

Is there a way to make this method more efficient? I am querying a

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Is there a way to make this method more efficient? I am querying a large number of transactions and it seems inefficient to perform a separate activerecord query for each period.

Should I make a single query for the whole day and sort through the results, grouping them by period? If so, what’s the most efficient way to do this? Look forward to your thoughts.

def self.transactions(period)
  today = Date.today
  time1 = Time.utc(today.year, today.month, today.day, 9, 30, 0)
  time2 = Time.utc(today.year, today.month, today.day, 16, 0, 0)
  transactions_by_period = {}

  while time1 < time2
    transactions = self.where("created_at >= ? and created_at <= ?", time1, time2)
    transactions_by_period[time1] = transactions
    time1 += period
  end

return transactions_by_period
end

#todays_transactions_by_hour = Stock.transactions(1.hour)
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  1. Editorial Team
    Editorial Team
    2026-06-17T10:10:56+00:00Added an answer on June 17, 2026 at 10:10 am

    First off, you can use ranges for nicer queries. I’d also rename time1 and time2 to start and finish

    transactions = self.where(:created_at => start..finish)
    

    Then you can reduce this to get them by periods.

    transactions.reduce(Hash.new{|h, k| h[k] = []) do |periods, transaction|
      # Calculate how many periods have gone by for this transaction
      offset = (transaction.created_at - start).to_i / period
      # Find the actual period
      transaction_period = start + offset * period
      periods[transaction_period] << transaction
      periods
    end
    

    Edit

    I haven’t tested the code, it is shown more for the logic

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