Question

Is there a way to match any class argument of the below sample routine?

class A {
     public B method(Class<? extends A> a) {}
}

How can I always return a new B() regardless of which class is passed into method? The following attempt only works for the specific case where A is matched.

A a = new A();
B b = new B();
when(a.method(eq(A.class))).thenReturn(b);

---

EDIT: One solution is

(Class<?>) any(Class.class)

Answer 1

Two more ways to do it (see my comment on the previous answer by @Tomasz Nurkiewicz):

The first relies on the fact that the compiler simply won’t let you pass in something of the wrong type:

when(a.method(any(Class.class))).thenReturn(b);

You lose the exact typing (the Class<? extends A>) but it probably works as you need it to.

The second is a lot more involved but is arguably a better solution if you really want to be sure that the argument to method() is an A or a subclass of A:

when(a.method(Matchers.argThat(new ClassOrSubclassMatcher<A>(A.class)))).thenReturn(b);

Where ClassOrSubclassMatcher is an org.hamcrest.BaseMatcher defined as:

public class ClassOrSubclassMatcher<T> extends BaseMatcher<Class<T>> {

    private final Class<T> targetClass;

    public ClassOrSubclassMatcher(Class<T> targetClass) {
        this.targetClass = targetClass;
    }

    @SuppressWarnings("unchecked")
    public boolean matches(Object obj) {
        if (obj != null) {
            if (obj instanceof Class) {
                return targetClass.isAssignableFrom((Class<T>) obj);
            }
        }
        return false;
    }

    public void describeTo(Description desc) {
        desc.appendText("Matches a class or subclass");
    }       
}

Phew! I’d go with the first option until you really need to get finer control over what method() actually returns 🙂