Question

Is there a way to print numbers from 1 to 100 without using any loops or conditions like “if”?
We can easily do using recursion but that again has an if condition. Is there a way to do without using “if” as well? Also no repetitive print statements, or a single print statement containing all the numbers from 1 to 100.

A solution in Java is preferable.

Answer 1

Pseudo code. Uses an array to force an exception after 100 elements which is caught and does nothing.

function r(array a, int index){
    a[index] = a[index-1]+1
    print a[index]
    r(a, index+1)
}

try{
    array a;
    a.resize(101)
    r(a, 1)
}catch(OutOfBoundsException){
}

EDIT
Java code:

public void printTo100(){
    int[] array = new int[101];
    try{
        printToArrayLimit(array, 1);
    }catch(ArrayIndexOutOfBoundsException e){
    }
}
public void printToArrayLimit(int[] array, int index){
    array[index] = array[index-1]+1;
    System.out.println(array[index]);
    printToArrayLimit(array, index+1);
}