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Home/ Questions/Q 6238915
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T11:17:58+00:00 2026-05-24T11:17:58+00:00

Is there a way to serialize (read/show) functions in Haskell? For example given that:

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Is there a way to serialize (read/show) functions in Haskell?

For example given that:

:t (+1) 
(+1) :: Num a => a -> a

I wish to be able to have something like:

read "(+1)" :: Num a => a -> a

Unfortunately this throws an error:

Could not deduce (Read (a -> a)) arising from a use of `read'
from the context (Num a)
  bound by an expression type signature: Num a => a -> a
  at <interactive>:1:1-30
Possible fix:
  add (Read (a -> a)) to the context of
    an expression type signature: Num a => a -> a
  or add an instance declaration for (Read (a -> a))
In the expression: read "(+1)" :: Num a => a -> a
In an equation for `it': it = read "(+1)" :: Num a => a -> a
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  1. Editorial Team
    Editorial Team
    2026-05-24T11:17:58+00:00Added an answer on May 24, 2026 at 11:17 am

    You could use something like the plugins package to read code at runtime. Showing is, as augustss says, impossible though.

    An example of how it could be used:

    import System.Eval.Haskell
    
    main = do
      mf <- eval "(+1) :: Int -> Int" []
      case mf of
        Just f -> print $ (f :: Int -> Int) 0
        _      -> putStrLn "Couldn't eval for some reason. :("
    
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