Question

Is there a way to specify regex that would match a string but from a certain position in this string? What I mean is that I have line:

"Somebodys_value is % value"  

and I’d like to check if my regex matches this sentence but only after % sign.

Answer 1

Using only RegEx you just include the % in your pattern. If your pattern is value, you can change it to %.*value.

---

Another way, that’s more dependent on your engine, is to provide an offset. You can use a strpos like function to find the %, and say to start matching after that.

---

Yet another method is to copy everything after the % into a new buffer/string, and then try to match that.

---

Any more specifics depend on the engine you’re using.

edit:
It sounds like you don’t want the % in your matches. A few implementation specific ways to do this are…

• (?:%).*value where the % is in a non-capturing group
• %\K.*value where \K discards everything before it (limited support)
• %(.*value) where you will just use the first subpattern (often called $1).
• or you can just do any operations starting at sub 1, and ignore the % at sub 0.