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Home/ Questions/Q 4270650
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T07:20:07+00:00 2026-05-21T07:20:07+00:00

Is there an efficient numpy mechanism to generate an array of values from a

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Is there an efficient numpy mechanism to generate an array of values from a 2D array given a list of indexes into that array?

Specifically, I have a list of 2D coordinates that represent interesting values in a 2D numpy array. I calculate those coordinates as follows:

nonzeroValidIndices = numpy.where((array2d != noDataValue) & (array2d != 0))
nonzeroValidCoordinates = zip(nonzeroValidIndices[0],nonzeroValidIndices[1])

From there, I’m building a map by looping over the coordinates and indexing into the numpy array one at a time similarly to this simplified example:

for coord in nonzeroValidCoordinates:       
    map[coord] = array2d[coord]

I have several massive datasets I’m iterating this algorithm over so I’m interested in an efficient solution. Through profiling, I suspect that array2d[coord] line is causing some pain. Is there a better vector form to generate an entire vector of values from array2d or am I stuck with indexing one at a time?

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  1. Editorial Team
    Editorial Team
    2026-05-21T07:20:08+00:00Added an answer on May 21, 2026 at 7:20 am

    I think you could try something like:

    array2d[ix_(nonzeroValidIndices[0],nonzeroValidIndices[1])]
    

    Or if you really want to use nonzeroValidCoordinates:

    unzip = lambda l: [list(li) for li in zip(*l)]
    array2d[ix_(unzip(nonzeroValidCoordinates))]
    

    Source: Link

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