Question

Is there another way to do this Query ?

 $query = "SELECT * FROM produto, pt WHERE
        produto.refPT = pt.ref AND
        produto.refPT IN (SELECT idProduto FROM amb_prod WHERE idAmbiente='1');";
    $result_set = mysql_query($query);

The problem is my localhost have the MySQL version 5.1.30-community, but my Online server have the 5.0.67-community MySQL version.

And I think is that the reason why I get this error only when I try to run on the online server:

mysql_fetch_array(): supplied argument is not a valid MySQL result resource 

Answer 1

It makes live easier when you create a nice view of your Query, like:

$query = "SELECT *
          FROM produto, pt, amb_prod 
          WHERE produto.refPT = pt.ref
          AND produto.refPT = amb_prod.idProduto 
          WHERE amb_prod.idAmbiente='1';";
$result_set = mysql_query($query);