Question

Is there any easy way to “join” the arguments passed to a script? I’d like something similar to $@, but that passes the arguments at once.

For example, consider the following script:

$/bin/bash

./my_program $@

When called as

./script arg1 arg2 arg3

my_program will receive the arguments as 3 separated arguments. What I want, is to pass all the arguments as one argument, joining them — separated by spaces, something like calling:

./my_program arg1\ arg2\ arg3

Answer 1

Use this one:

./my_program "$*"