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Home/ Questions/Q 8371877
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T14:16:02+00:00 2026-06-09T14:16:02+00:00

Is there any limitations in functions declaring? For example, this piece of code returning

  • 0

Is there any limitations in functions declaring?

For example, this piece of code returning unsat.

from z3 import *

def one_op (op, arg1, arg2):
    if op==1:
        return arg1*arg2
    if op==2:
        return arg1-arg2
    if op==3:
        return arg1+arg2

    return arg1+arg2 # default

s=Solver()

arg1, arg2, result, unk_op=Ints ('arg1 arg2 result unk_op')

s.add (unk_op>=1, unk_op<=3)

s.add (arg1==1)
s.add (arg2==2)
s.add (result==3)
s.add (one_op(unk_op, arg1, arg2)==result)

print s.check()

How Z3Py interpret declared function? Is it just calling it some times or some hidden machinery also here?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T14:16:04+00:00Added an answer on June 9, 2026 at 2:16 pm

    In the function call one_op(unk_op, arg1, arg2), unk_op is a Z3 expression. Then, expressions such as op==1 and op==2 (in the definition of one_op) are also Z3 symbolic expressions. Since op==1 is not the Python Boolean expression False. The function one_op will always return the Z3 expression arg1*arg2. We can check that by executing print one_op(unk_op, arg1, arg2). Note that the if statements in the definition of one_op are Python statements.

    I believe your true intention is to return a Z3 expression that contains conditional expressions. You can accomplish that by defining one_op as:

    def one_op (op, arg1, arg2):
        return  If(op==1,
                   arg1*arg2,
                   If(op==2,
                      arg1-arg2,
                      If(op==3,
                         arg1+arg2,
                         arg1+arg2)))
    

    Now, the command If builds a Z3 conditional expression. By using, this definition, we can find a satisfying solution. Here is the complete example:

    from z3 import *
    
    def one_op (op, arg1, arg2):
        return  If(op==1,
                   arg1*arg2,
                   If(op==2,
                      arg1-arg2,
                      If(op==3,
                         arg1+arg2,
                         arg1+arg2)))
    
    s=Solver()
    
    arg1, arg2, result, unk_op=Ints ('arg1 arg2 result unk_op')
    
    s.add (unk_op>=1, unk_op<=3)
    s.add (arg1==1)
    s.add (arg2==2)
    s.add (result==3)
    s.add (one_op(unk_op, arg1, arg2)==result)
    
    print s.check()
    print s.model()
    

    The result is:

    sat
    [unk_op = 3, result = 3, arg2 = 2, arg1 = 1]
    
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