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Home/ Questions/Q 3609850
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T21:40:46+00:00 2026-05-18T21:40:46+00:00

Is there any portable way to determine what the maximum possible alignment for any

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Is there any portable way to determine what the maximum possible alignment for any type is?

For example on x86, SSE instructions require 16-byte alignment, but as far as I’m aware, no instructions require more than that, so any type can be safely stored into a 16-byte aligned buffer.

I need to create a buffer (such as a char array) where I can write objects of arbitrary types, and so I need to be able to rely on the beginning of the buffer to be aligned.

If all else fails, I know that allocating a char array with new is guaranteed to have maximum alignment, but with the TR1/C++0x templates alignment_of and aligned_storage, I am wondering if it would be possible to create the buffer in-place in my buffer class, rather than requiring the extra pointer indirection of a dynamically allocated array.

Ideas?

I realize there are plenty of options for determining the max alignment for a bounded set of types: A union, or just alignment_of from TR1, but my problem is that the set of types is unbounded. I don’t know in advance which objects must be stored into the buffer.

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  1. Editorial Team
    Editorial Team
    2026-05-18T21:40:47+00:00Added an answer on May 18, 2026 at 9:40 pm

    In C++0x, the Align template parameter of std::aligned_storage<Len, Align> has a default argument of “default-alignment,” which is defined as (N3225 §20.7.6.6 Table 56):

    The value of default-alignment shall be the most stringent alignment requirement for any C++ object type whose size is no greater than Len.

    It isn’t clear whether SSE types would be considered “C++ object types.”

    The default argument wasn’t part of the TR1 aligned_storage; it was added for C++0x.

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