Is there any real way to represent a URL (which more than likely will also have a query string) as a filename in Java without obscuring the original URL completely?
My first approach was to simply escape invalid characters with arbitrary replacements (for example, replacing “/” with “_”, etc).
The problem is, as in the example of replacing with underscores is that a URL such as “app/my_app” would become “app_my_app” thus obscuring the original URL completely.
I have also attempted to encode all the special characters, however again, seeing crazy %3e %20 etc is really not clear.
Thank you for any suggestions.
Well, you should know what you want here, exactly. Keep in mind that the restrictions on file names vary between systems. On a Unix system you probably only need to escape the virgule somehow, whereas on Windows you need to take care of the colon and the question mark as well.
I guess, the safest thing would be to encode anything that could potentially clash (everything non-alphanumeric would be a good candidate, although you migth adapt this to the platform) with percent-encoding. It’s still somewhat readable and you’re guaranteed to get the original URL back.