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Home/ Questions/Q 6232873
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T10:11:41+00:00 2026-05-24T10:11:41+00:00

Is there any reason that this: function find_parent_p(x){ daddy = jQuery(x).parent(); if(daddy.attr(tagName).toLowerCase() == ‘p’){

  • 0

Is there any reason that this:

function find_parent_p(x){
    daddy = jQuery(x).parent();


    if(daddy.attr("tagName").toLowerCase() == 'p'){
        console.log(daddy,"result");
        return (daddy);
    } else {
        find_parent_p(daddy);

    }

}
jQuery(document).ready(function($){

        $('img').each(function(){

            next = find_parent_p($(this));

        })


});

would return a jQuery object in the console (expected behaviour), where as the following returns Undefined All I am doing is moving the call to console.log outside the function, and after the call to it:

function find_parent_p(x){
    daddy = jQuery(x).parent();


    if(daddy.attr("tagName").toLowerCase() == 'p'){

        return (daddy);
    } else {
        find_parent_p(daddy);

    }

}
jQuery(document).ready(function($){

        $('img').each(function(){

            next = find_parent_p($(this));
                    console.log(next,"result");

        })


});
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T10:11:42+00:00Added an answer on May 24, 2026 at 10:11 am

    You’re missing the return statement in your else condition. If your function recurses, then the top level call won’t return anything, and you’ll end up with undefined.

    else {
        return find_parent_p(daddy);
    
    }
    
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