Question

Is there any shorter expression to get DOM nods via XPath, more concise from following command that need a lot of variables.

doc.evaluate(xpath, doc, nsResolver, XPathResult.ANY_TYPE, null);  

Answer 1

As far as I know Firefox only supports the DOM Level 3 XPath API, part of which the evaluate function is. If you want something shorter then you need to roll your own (or find a library which does it for you) or you need to use a different browser, for instance with Opera you can do e.g. node.selectSingleNode(path [,nsResolver]) to select a single node, with node.selectNodes(path [, nsResolver]) you can select a DOM NodeList of nodes. Within MSXML’s XML DOM implementation you use with IE you also have selectSingleNode and selectNodes function although namespace handing there is different from the Opera implementation as with MSXML you need to use document.setProperty('SelectionNamespaces', 'xmlns:pf1="http://example.com/ns1" xmlns:pf2="http://example.com/ns2"').