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Home/ Questions/Q 6579431
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T15:53:50+00:00 2026-05-25T15:53:50+00:00

Is there any way in Python to continue iterating after exception throwed by iterator/generator?

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Is there any way in Python to continue iterating after exception throwed by iterator/generator? Like in code below, is there any way to skip ZeroDivisionError and continue looping through gener() without modyfying run() function?

def gener():
    a = [1,2,3,4,0, 5, 6,7, 8, 0, 9]
    for i in a:
        yield 2/i

def run():
    for i in gener():
        print i

#---- run script ----#

try:
    run()
except ZeroDivisionError:
    print 'what magick should i put here?'
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  1. Editorial Team
    Editorial Team
    2026-05-25T15:53:51+00:00Added an answer on May 25, 2026 at 3:53 pm

    The logical place for the try/except would be the place where the offending calculation takes place:

    def gener():
        a = [1,2,3,4,0, 5, 6,7, 8, 0, 9]
        for i in a:
            try:
                yield 2/i
            except ZeroDivisionError:
                pass
    
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