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Home/ Questions/Q 7794411
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T22:46:01+00:00 2026-06-01T22:46:01+00:00

Is there any way not to leave <choose> after first <when> match but continue

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Is there any way not to leave <choose> after first <when> match but continue check else conditions?

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  1. Editorial Team
    Editorial Team
    2026-06-01T22:46:04+00:00Added an answer on June 1, 2026 at 10:46 pm

    I believe it’s a no. As the spec says:

    The content of the first, and only the first, xsl:when element whose
    test is true is instantiated. If no xsl:when is true, the content of
    the xsl:otherwise element is instantiated. If no xsl:when element is
    true, and no xsl:otherwise element is present, nothing is created.

    from: http://www.w3.org/TR/xslt#section-Conditional-Processing-with-xsl:choose

    you can’t make it fall through other conditions like that. just convert it into a set of <xsl:if> following one another if you need a fall through

    UPDATE. Here’s a quote from the O’Reilly’s XSLT book ( http://docstore.mik.ua/orelly/xml/xslt/ch04_02.htm ):

    The C, C++, and Java switch statement is roughly equivalent to the
    element. The one exception is that procedural languages
    tend to use fallthrough processing. In other words, if a branch of the
    switch statement evaluates to true, the runtime executes everything
    until it encounters a break statement, even if some of that code is
    part of other branches. The element doesn’t work that
    way. If a given evaluates to true, only the statements
    inside that are evaluated

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