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Home/ Questions/Q 8479815
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T19:08:16+00:00 2026-06-10T19:08:16+00:00

Is there any way to avoid the delay caused by the JVM starting up

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Is there any way to avoid the delay caused by the JVM starting up each time you run an exec command in PHP?

I have two JARs for encryption and decryption that I need to run using PHP. Both run on the same script although one decrypts a URL parameter and then the other encrypts some other information. When I run them through the command line, they both finish in less than 0.4 seconds each. However, when I run them using the PHP exec function, a new instance of the JVM is started which adds 5 seconds onto each JAR execution time.

I have investigated using Nailgun but can’t get that to work. I can’t find any documentation for getting it to run a JAR and when I use classes, it can never find them either.

I have also considered using PHP/Java Bridge. I would prefer however to continue using exec. I am already running IIS 7.5 and I am not sure how one would configure the bridge to work with this.

My question is this:
Is there any way to keep the JVM running in the background in such a way that the PHP exec function does not need to start a new instance each time? I think there must be a way as there is no delay through the command line.

If there is no way of doing this, then I am open to other suggestions. 11 seconds to run a PHP script means that visitors to the website will most likely leave.

Additional information that may or may not be of use:

It will be running on Windows Server 2008 R2 32-bit OS.

Local access required only.

IIS server 7.5 being used.

Website is coded in PHP. PHP version is 5.3.5.

Server is running the latest JRE – Java7 u6

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  1. Editorial Team
    Editorial Team
    2026-06-10T19:08:18+00:00Added an answer on June 10, 2026 at 7:08 pm

    Is there any way to keep the JVM running in the background in such a way that the PHP exec function does not need to start a new instance each time?

    You can start a ServerSocket on a known port.

    If its the first time the application has run, this will be successful and this process can keep running.

    If this is not successful, the application can open a Socket on that port and send the command as required and get the response.

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