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Home/ Questions/Q 8334703
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T03:26:27+00:00 2026-06-09T03:26:27+00:00

Is there any way to combine xml-based layout and manual layout? F.ex.: I use

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Is there any way to combine xml-based layout and “manual” layout? F.ex.:

I use the “standard” xml layout like this:

 setContentView(R.layout.mainscreen);

And then I want to have some more dynamic contents, adding it like this:

 LinearLayout layout = new LinearLayout(this);
 setContentView(layout);
 layout.addView(new CreateItemButton(this, "Button", 1));

I realize of cours that I cannot create a new layout like in the line above, but I’d probably have to initialize the xml layout in some way. But – is it possible, or do I just have to go with a 100% manual layout if I want to dynamically add components? Or is there perhaps another, more elegant/correct way of doing it?

(What I want to do is create buttons based on entries fetched from a database. These will wary in number and text/contents, hence the attempt to add them dynamically instead of in the xml layout file.

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  1. Editorial Team
    Editorial Team
    2026-06-09T03:26:29+00:00Added an answer on June 9, 2026 at 3:26 am

    You can add any element dynamically to your xml layout.
    You have to have a container in your xml layout where you are going to add your dynamic elements. Say empty LinearLayout with id=”container”. Also you can build everything dynamically and setContentView(yourView); Where is yourView is a root layout element with other child elements added.

    EX:

    Button myButton = new Button(this);
    myButton.setLayoutParams(params);
    LinearLayout container = (LinearLayout)findViewById(R.id.container);
    container.addView(myButton);
    

    or

    LinearLayout myLayout = new LinearLayout(this);  
    ...
    container.addView(myLayout);
    
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