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Home/ Questions/Q 6705831
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T07:26:59+00:00 2026-05-26T07:26:59+00:00

Is there any way to construct an array of strings inside a function call?

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Is there any way to construct an array of strings inside a function call? For example, say I have a function like this:

void foo( char * [] strings )
{
    //...does stuff
}

And instead of declaring the character array first and then passing it, is there any way, with arrays or any other container class, to call the function like this?

foo( { "a", "b", "c", ...} );

Basically I have a function that prompts a user for input until it matches one of the strings in the array I pass, and since that changes throughout the program, I pass the accepted inputs into the function that prompts the user and validates the input. Currently I am just constructing it outside the function and passing it in but was wondering if they could be combined into one line in any way

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T07:27:00+00:00Added an answer on May 26, 2026 at 7:27 am

    This works in C99:

    void fun(char *argv[])
    {
        while(*argv)
            printf("%s\n", *argv++);
    }
    
    fun((char*[]){"aaa", "bbb", NULL});
    

    Since you mention “container” you probably use C++ so this answer is of limited value (unless you are using a compiler that accepts it as an extension – the way GCC does for example).

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