Question

Is there any way to do something like this?

void SomeMethod(Type generic)
{
    SomeGenericMethod<generic>();
}

I need to pass the type in as a “normal” parameter and not a generic type parameter.

Answer 1

You can do it with reflection:

public class foo
{
    public void SomeMethod(Type type)
    {
        var methodInfo = this.GetType().GetMethod("SomeGenericMethod");
        var method = methodInfo.MakeGenericMethod(new[] { type });
        method.Invoke(this, null);
    }

    public void SomeGenericMethod<T>()
    {
        Debug.WriteLine(typeof(T).FullName);
    }
}

class Program
{
    static void Main(string[] args)
    {
        var foo = new foo();
        foo.SomeMethod(typeof(string));
        foo.SomeMethod(typeof(foo));
    }
}

That said, using reflection in this way means you are losing some of the benefits of using generics in the first place, so you might want to look at other design alternatives.