Question

Is there any way to exit from the method? I hear that there are two way to exit.

One : throw Exception.

public void dosomething() {
    if(...) {
        throw new MyException();
    }
             // there might be another process.

}

Two : return somevalue. Even void method, we can return the value.

public void dosomething() {
    if(...) {
        return;
    }
             // there might be another process.
}

Question is, Is there any better way?

Answer 1

Technically you could System.exit(int) (the int value would be the value returned from the process and likely non-zero to indicate an error). It’s a little brutal, however.

You can also interrupt yourself.

Thread.currentThread().interrupt();

However:

1. this is still an exception. You’re not throwing it explicitly, but it still results in an InterruptedException
2. your thread has to perform some IO/sleep operation subsequently to register this interruption. If it’s solely computational then it won’t exit due to this.

e.g. (note the sleep() to catch the interruption):

public class Test {
  public static void method() throws Exception {
    Thread.currentThread().interrupt();
    Thread.sleep(100);
    System.out.println("method done");
  }
  public static void main(String[] args) throws Exception {
    method();
    System.out.println("done");
  }
}

gives me:

Exception in thread "main" java.lang.InterruptedException: sleep interrupted
        at java.lang.Thread.sleep(Native Method)
        at T.method(T.java:5)
        at T.main(T.java:9)