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Home/ Questions/Q 6197021
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T03:44:51+00:00 2026-05-24T03:44:51+00:00

Is there any way to force operator precedence in Scala like you do in

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Is there any way to force operator precedence in Scala like you do in Haskell with $?

For example, in Haskell, you have:

a b c = ((a b) c)

and

a $ b c = a (b c)

Is there a similar way to do this in Scala? I know Scala doesn’t have operators per se, but is there a way to achieve a similar effect?

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  1. Editorial Team
    Editorial Team
    2026-05-24T03:44:51+00:00Added an answer on May 24, 2026 at 3:44 am

    infix vs . notation is often used in a similar fashion to control precedence:

    a b c d == a.b(c).d
    a.b c d == a.b.c(d)
    a b c.d == a.b(c.d)
    

    Scala also has a fixed precedence ordering for operators used in infix notation:

    (all letters)
    |
    ^
    &
    < >
    = !
    :
    + -
    * / %
    (all other special characters)
    

    Names can usually chosen explicitly to take advantage of this. For example, ~ and ^^ in the standard parsers library.

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