Question

Is there any way to remove variable “i” in the following example and still get access to index of item that being printed ?

def i = 0;
"one two three".split().each  {
    println ("item [ ${i++} ] = ${it}");
}

=============== EDIT ================

I found that one possible solution is to use “eachWithIndex” method:

"one two three".split().eachWithIndex  {it, i
    println ("item [ ${i} ] = ${it}");
}

Please do let me know if there are other solutions.

Answer 1

you can use eachWithIndex()

"one two three four".split().eachWithIndex() { entry, index ->
      println "${index} : ${entry}" }

this will result in

0 : one
1 : two
2 : three
3 : four