Question

Is there any way to round a float to the nearest decimal place in processing?

For example

float x = 1.0000001
float y = 1.1000000001

float a = x + y
round(a)

a = 2.10

The standard round() in processing rounds to the nearest whole number, but I need to have the decimals in place. I can’t find a function that does what I’m looking for. I have some floats with over a hundred decimal places so I need to trim them down, if its possible.

Answer 1

Here is a function that is more processing-centric:

float fixDec(float n, int d) {
  return Float.parseFloat(String.format("%." + d + "f", n));
}

and to test it:

float x = 1.0000001;
float y = 1.1000000001;
x = fixDec(x, 2);
y = fixDec(y, 2);
float a = x + y;
round(a);

this is probably not the most efficient algorithm, but it works.