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Home/ Questions/Q 8922183
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T06:46:10+00:00 2026-06-15T06:46:10+00:00

Is there any way to use DLR to reference a method in C#? In

  • 0

Is there any way to use DLR to reference a method in C#?

In dynamic languages like JavaScript or Python I could easily pass a method as an argument to another method. In C# being statically typed language, I either use Delegate type which needs lots of casting:

public static void AddMethod(Delegate del)
{
    // implementation
}

and then use casting whenever I call this method

static void Main(string[] args)
{
    AddMethod(new Func<object, bool>(Test));
}

public static bool Test(object obj)
{
    return true;
}

Or, I need to define dozens of overloads to satisfy any method calls:

public static void AddMethod<TResult>(Func<TResult> method)
{
}

public static void AddMethod<T, TResult>(Func<T, TResult> method)
{
}

public static void AddMethod<T1, T2, TResult>(Func<T1, T2, TResult> method)
{
}

public static void AddMethod<T1, T2, T3, TResult>(Func<T1, T2, T3, TResult> method)
{
}

Is there any cleaner way to define an argument as a placeholder for all other methods? (I’m trying to avoid MethodInfo or other Reflection stuff here)

I was trying something like this:

public delegate dynamic DynamicDelegate(params dynamic[] args);

public static void AddMethod(DynamicDelegate method)
{
}

But the compiler doesn’t seem to accept a statically typed method for a dynamically declared delegates!

Any other thoughts?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T06:46:11+00:00Added an answer on June 15, 2026 at 6:46 am

    You can use a simple Action

    void AddMethod(Action action) //or void AddMethod(Func<TResult> fxn)
    {
    }
    

    and call as

    AddMethod(()=>Test(obj));   
    

    or

    AddMethod(()=>Test(obj1,obj2));   
    

    –EDIT–

    AddMethod(() => Math.Max(1,3));  
    AddMethod(() => (int)Math.Sqrt(4));
    AddMethod(() => new int[]{8,5,6}.Min())
    
    void AddMethod(Func<int> fxn)
    {
         int i = fxn() * fxn();  // <---
    }
    
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