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Home/ Questions/Q 8877293
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T19:26:01+00:00 2026-06-14T19:26:01+00:00

Is there any way using Code Contracts to ensure/check that a method does not

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Is there any way using Code Contracts to ensure/check that a method does not change any members of an object, similarly to C++ const methods or setting all the members to readonly?

i.e. a simpler way than the following:

Contract.Ensures(this.member1 == Contract.OldValue(this.member1));
Contract.Ensures(this.member2 == Contract.OldValue(this.member2));
Contract.Ensures(this.member3 == Contract.OldValue(this.member3));
Contract.Ensures(this.member4 == Contract.OldValue(this.member4));
Contract.Ensures(this.member5 == Contract.OldValue(this.member5));

or the same using Contract.EnsuresOnThrow.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T19:26:03+00:00Added an answer on June 14, 2026 at 7:26 pm

    So essentially you want to check that the method is Pure. The official documentation indicates that its not yet supported (see section 5.4):

    5.4 Purity
    
    All methods called within a contract must be pure: that is, they must not update
    any pre-existing state. (A pure method is allowed to modify objects that have been
    created after entry into the pure method.) Code Contract tools currently assume
    the following things are pure:
    
    * Methods marked [Pure] (If a type is marked [Pure], then that applies to all of
      its methods.) The pure attribute is dened in the contract library. (Section 4.3)
    
    * Property getters.
    
    * Operators (static methods whose names start with op , have one or two parameters
      and a non-void return type).
    
    * Any method whose fully qualified name begins with
      System.Diagnostics.Contracts.Contract, System.String, System.IO.Path, or
      System.Type.
    
    * Any invoked delegate, provided that the delegate type itself is attributed with
      [Pure]. The existing delegate types System.Predicate<T> and System.Comparison<T>
      are considered pure.
    
    In the future, there will be a purity checker that will enforce these assumptions.
    
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